Placement Preparation- Topic Simplification & Approximation - QA


Placement Preparation Questions on Simplification & Approximation for Campus Recruitment

What is Campus Recruitment Process?

Generally, a Campus Placement Process has four components:

 * Pre Placement Talk 

 * Aptitude test 

 * Group Discussion 

 * Interview which can be various combinations of Technical and HR rounds 

Aptitude Test for Placements:

The Aptitude test consists of basic problems in quantitative ability, logical reasoning, and verbal ability. The primary objective of this test is to check the problem-solving skills of the test-taker. Any job out there is the problem-solving skills. It is essential to understand what the problem is and how the problem should be solved. So, the application of the learning is the Aptitude test.

Take a Free Campus Placement Mock Test

Please read the below blogs to know the detailed campus recruitment process of respective companies: 

Amazon Recruitment Process TCS Recruitment Process
IBM Recruitment Process Capgemini Recruitment Process
Wipro Recruitment Process Deloitte Recruitment Process
Tech Mahindra Recruitment Process Infosys Recruitment Process
Cognizant Recruitment Process Accenture Recruitment Process

Tips and Tricks to solve the Simplification and Approximation Questions for Campus Recruitment Test

  • If you want to stand out & beat the competition in your Campus Placements, the first step is to ace the Written Aptitude Test. Quantitative Aptitude contributes a lot to increase your scores. No aptitude test is complete without questions based on Simplification & Approximations.
  • Methods of learning in one chapter can be used in other chapters.
  • Whether the Question is simple or difficult you can know the options.
  • Focus on all areas in quantitative will help you crack quantitative section

Watch the below video to learn Tips & Tricks to crack Questions on Simplification and Approximation in Campus Recruitment Exams.

The Following questions are based on Simplification and Approximation:

Simplification involving Large Numbers:

1. -87+1934-271-?=893





Answer: B


From the given question  Do you notice all the option are very close to each other

Do you notice except the first and last option remaining two options have a different unit digit at the end of the number

Now we have to take the unit digit of each number along with the sign


Instead of taking the 4 we have to take 14 or 24 and so on

Because if we take the number 4 it will get negative digits. But our answer is in positive 

So, we have to take 14 instead of 4



In the place of the question mark,  the number 3 has to come

According to the option, the unit digit which ends with 3 is 683.

2. 12738-2314-1781+9816=?





Answer: A


First part

Look at the following options 459&461 are repeated two times

The unit digit could be 1 or 9

Based on that we have to eliminate two options

Second part

The unit digit of each number will be


we need the number ending with '9' 

so, 2&4 options are eliminated

Now we are Looking at the thousand terms 


It will be 18000

Third part

Suppose if we have two options starting with 18 and the units place is 9 we have to use the third part

From the above question, we have two 7 hundred numbers if they are canceled it get -50 or -40 difference

Then 816 & -314 it will get 500 difference(18000-50+500)

So, the answer is approximately equal to 18,450

so the answer is 18,459.

Simplification involving Fractions

3. 3 4/5+5 6/7=

A.9 23/35

B.9 24/35

C.9 25/35

D.9 33/35

Answer: A


First, we have to consider


Then 9 ?/?

we know that denominator should be 5 or 7 or 35

For the safe, you have to assume 35

then 9 ?/35

The numerator will be 23 or 24 or 25 

Because of the fraction should be 0.65

But in the given options numerator has given 23,24,25

so we have to find  given numerator

3+4/5+5+6/7=8+(28+30)/35=8+1+23/25=9 23/35

4. 3 4/5+? 3/8=9 ?/40





Answer: C


Here 9 ?/40 in this '?' should be less than 40

Step 1 Isolate the whole & fraction


Step 2 Estimate the whole number


'x' should be equal to 5 due to '9'

Step 3 Simplifying the fraction


Here 7/40 is the fraction

so, the answer is 5,7

5. 4 3/7-8 2/5+6 1/5-7 4/7=?

A.-4 15/35

B.-5 12/35

C.-5 15/35

D.-4 12/35

Answer: B


whole numbers                 fractions

 4                                        +3/7

-8                                        -2/5

+6                                       +1/5

-7                                         -4/7

-5                                          -(1/7)-(1/5)

-[5+1/7+1/5]=-[5+12/35]=-5 12/35

Practice Top 30 Company's Aptitude Questions with 135 Test Papers
Read 188 times Last modified on Friday, 31 August 2018 14:55
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