Placement Preparation Questions on Simplification & Approximation for Campus Recruitment
What is Campus Recruitment Process?
Generally, a Campus Placement Process has four components:
* Pre Placement Talk
* Aptitude test
* Group Discussion
* Interview which can be various combinations of Technical and HR rounds
Aptitude Test for Placements:
The Aptitude test consists of basic problems in quantitative ability, logical reasoning, and verbal ability. The primary objective of this test is to check the problem-solving skills of the test-taker. Any job out there is the problem-solving skills. It is essential to understand what the problem is and how the problem should be solved. So, the application of the learning is the Aptitude test.
Please read the below blogs to know the detailed campus recruitment process of respective companies:
Tips and Tricks to solve the Simplification and Approximation Questions for Campus Recruitment Test
- If you want to stand out & beat the competition in your Campus Placements, the first step is to ace the Written Aptitude Test. Quantitative Aptitude contributes a lot to increase your scores. No aptitude test is complete without questions based on Simplification & Approximations.
- Methods of learning in one chapter can be used in other chapters.
- Whether the Question is simple or difficult you can know the options.
- Focus on all areas in quantitative will help you crack quantitative section
Watch the below video to learn Tips & Tricks to crack Questions on Simplification and Approximation in Campus Recruitment Exams.
The Following questions are based on Simplification and Approximation:
Simplification involving Large Numbers:
From the given question Do you notice all the option are very close to each other
Do you notice except the first and last option remaining two options have a different unit digit at the end of the number
Now we have to take the unit digit of each number along with the sign
Instead of taking the 4 we have to take 14 or 24 and so on
Because if we take the number 4 it will get negative digits. But our answer is in positive
So, we have to take 14 instead of 4
In the place of the question mark, the number 3 has to come
According to the option, the unit digit which ends with 3 is 683.
Look at the following options 459&461 are repeated two times
The unit digit could be 1 or 9
Based on that we have to eliminate two options
The unit digit of each number will be
we need the number ending with '9'
so, 2&4 options are eliminated
Now we are Looking at the thousand terms
It will be 18000
Suppose if we have two options starting with 18 and the units place is 9 we have to use the third part
From the above question, we have two 7 hundred numbers if they are canceled it get -50 or -40 difference
Then 816 & -314 it will get 500 difference(18000-50+500)
So, the answer is approximately equal to 18,450
so the answer is 18,459.
Simplification involving Fractions
3. 3 4/5+5 6/7=
First, we have to consider
Then 9 ?/?
we know that denominator should be 5 or 7 or 35
For the safe, you have to assume 35
then 9 ?/35
The numerator will be 23 or 24 or 25
Because of the fraction should be 0.65
But in the given options numerator has given 23,24,25
so we have to find given numerator
4. 3 4/5+? 3/8=9 ?/40
Here 9 ?/40 in this '?' should be less than 40
Step 1 Isolate the whole & fraction
Step 2 Estimate the whole number
'x' should be equal to 5 due to '9'
Step 3 Simplifying the fraction
Here 7/40 is the fraction
so, the answer is 5,7
5. 4 3/7-8 2/5+6 1/5-7 4/7=?
whole numbers fractions