Deloitte Quant Questions & Answers Online for Freshers
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Quantitative Ability for Deloitte Online Exam:
This section consists of 25 questions and the time allotted is 35 minutes.
Quantitative Ability syllabus for Deloitte:
Questions on logarithms, Probability, Simple Interest and Compound Interest, Permutations and Combinations, arrangement puzzles, HCF and LCM. The difficulty level of the paper is moderate.
Sample questions for Deloitte Quantitative Ability:
1. log√3 / log3 is equivalent to?
A. log √3
log√3 / log3 = 1/2log3 / log3 = 1/2
Read More: Ace Verbal Ability To Land in Your Dream Job
2. Events A and B we have : P(A B) =?
A. P(A) + P(B) - P(A B)
B. P(A) + P(B) + P(A B)
C. P(A) + P(B) - P(A B)
D. P(A) + P(B) + P(A B)
According to the formula:
For any events A and B we have : P(A B) = P(A) + P(B) - P(A B)
3. If A denotes (not-A), then P(A) =?
B. 1 + P(A)
C. P(A) -1
D. 1 - P(A).
According to the formula:
If A denotes (not-A), then P(A) = 1 - P(A).
4. Two numbers are in the ratio 2 : 3. If their L.C.M. is 48. what is the sum of the numbers?
Let the numbers be 2x and 3x
LCM of 2x and 3x= 6x (LCM of 2 and 3 is 6. Hence LCM of 2x and 3x is 6x)
Given that LCM of 2x and 3x is 48
6x = 48
x = 8
The sum of the numbers
= 5 * 8 = 40
5. How much time will it take for an amount of Rs.275 to yield Rs. 51 as interest at 3.25% per annum of simple interest?
A. 5.7 years
B. 4.8 years
C. 3.5 years
D. 6.1 years
Time =(100 * 51 / 275 * 3.25)years= 5.7 years.
6. If Rs.30,000 is invested at 15% p.a. for 3 years, then find the total amount under Compound Interest?
The formula is used to find total amount: A= P [1+ R/100]n
Where, P= 30,000, R= 15, n=3
A = 30000 [1 + (15/100)]3
A = Rs. 45626/-
7. The number of all permutations of n things, taken r at a time, is given by:
A. n / (n - r)!
B. n!/ (r - n)!
C. n! /(n - r)!
D. r! /(n - r)!
The number of all permutations of n things, taken r at a time, is given by:
nPr = n(n - 1)(n - 2) ... (n - r + 1) = n! / (n - r)!
8. Study the following information carefully and answer the questions given below:
There are eight persons, namely A, B, C, D, E, F, G and H, who live on eight different floors from one to eight. The ground floor is numbered 1 and the top floor is numbered eight. Only three persons live below the floor on which E lives. Two persons live between the floors on which E and H live. More than one person live between the floor on which A and E live. C lives immediately above G. C live on the odd numbered floor. Only one person lives between B and F. B lives two floors above on which F lives. D lives on the even numbered floor but not on the 2nd floor.
a) Who lives on floor number 2?
So, G lives on floor number 2
b) How many persons live between D and C?
So, 2 persons live between D and C
c) Who lives just top to A?
So, Nobody is living just top to A
d) Who lives on the fifth floor?
So, F is living on the fifth floor
e) Who lives Just below to D?
So, F lives Just below to D
9. H.C.F of fractions is defined as:
A. H.C.F of Numerators / L.C.M of denominators
B. L.C.M of Numerators / H.C.F of denominators
C. L.C.M of Numerators / L.C.M of denominators
D. H.C.F of Numerators / H.C.F of denominators
According to H.C.F of fractions Formula:
H.C.F = H.C.F of Numerators / L.C.M of denominators
10. The greatest number of three digits which is divisible by 4, 6, and 12 is:
L.C.M. of 4, 6 and 12 is 12.
The greatest number of 3-digits is 999.
On dividing 999 by 12, the remainder is 3.
→The greatest number is (999 - 3) = 996.
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