**NTT Data Quantitative Aptitude Placement Test Questions**

NTT Data is going to hire students from campus. Are you looking for resources to get yourself ready for the placement challenge? Here is a set of Quant questions based on previous years’ NTT Data Placement Papers.

NTT Data Test pattern consists of four sections Quantitative Aptitude,Logical Reasoning,English and Computer Programming consisting of total 100 questions in 120 minutes. Quantitative Aptitude section consists of 25 questions and time allotted is 35 minutes.

**NTT Data Quantitative Aptitude Questions and Answers**

This article covers some of the quant question based on the previous year’s pattern related to LCM & HCF, Divisibility, numbers, Profit & Lost, Simple and Compound interest, Time, speed and Distance, log and probability. You can go through the following sample questions to make yourself ready for NTT Data Placement Test.

Directions for Questions 1 to 8: Choose the correct options in the below questions.**1. The ratio of two numbers is 5: 6 and their HCF is 34. Find their LCM.**

a) 204

b) 1020

c) 170

d) 510**Explanation:**

Let the two numbers be 5X and 6X. Since, their HCF = 34. Therefore, X = 34

We know that, Product of two numbers = HCF X LCM

Therefore, 5 * 34 * 6 * 34 = 34 * LCM LCM = 1020

The correct answer is **Option B****2. When integer “N” is divided by 6, it gives a remainder of 4. What is the remainder when “5N” is divided by 6?**

a) 3

b) 2

c) 0

d) 1**Explanation:**

Since, when N is divided by 6 it gives the remainder of 4. Number N can be written as:

N = 6k + 4, Now, Multiply N by 5 => 5N = 30k + 20. It can also be written as 6 * (5k) + 18 + 2 => 6 * (5k + 3) + 2

Therefore, new Number N = 6 * (5k + 3) + 2, when it is divided by 6 it leaves remainder 0 for “6 * (5k + 3)” part and 2 remainder for other part. So, total Remainder = 0+2 = 2

The correct answer is **Option B****3. What is the sum of numerator and denominator when 0.448 is written in simplest fractional form?**

a) 1448

b) 362

c) 724

d) 181**Explanation:**

0.448 can be written as 448/1000

A Simplest fractional form is the form in which common factor cannot be taken out further. Therefore, simplest fractional form will be 56/125

The correct answer is **Option D****4. When a merchant sold an article for Rs 1105, he incurred a loss of 15 percent. For how much price the article should be sold to get a profit of 25 percent?**

a) 1625

b) 1300

c) 1200

d) 1250**Explanation:**

Let the cost price of an article is X. So, X – 0.15X = 1105 (Since merchant sold the article at a loss of 15 percent)

Therefore, Cost price X = 1300. Now, to earn a profit of 25 percent Selling price = X + .25X = 1625

The correct answer is **Option A****5.** **A train of length 210 meters and speed 65 Km/hour passes a platform in 45 seconds. Find the length of the platform.**

a) 775.24 metres

b) 800 meters

c) 812.75 meters

d) 825 meters**Explanation:**

Speed of train = 65 km/hour = (65 * 1000) * 3600 = 18.055 m/sec

Let the length of platform is X. Therefore, (210+X) = 18.055 * 45 [Distance travelled = Speed * Time]X = 812.475 metres

The correct answer is **Option C****6.** **If 8 birds make 8 nests in 8 days. In how many days 1 bird makes 1 nest?**

a) 64

b) 4

c) 8

d) 1**Explanation:**

Work done in 1 day by 8 birds = number of nest/number of days = 8/8 =>1

Work was done by 1 bird in a day = 1/8

Therefore, the number of days required by 1 bird to make 1 nest = 8 days

Therefore, the correct answer is **Option C****7.** **What is the probability that the sum of the number **on** faces is 10 when two unbiased dice are rolled?**

a) 1/12

b) 1/6

c) 1/18

d) 1/9**Explanation:**

Since there are 6 faces on each dice. So, the total number of outcomes = 6 * 6 = 36

Number of total favourable outcomes are {4,6}, {5,5}, {6,4}

Therefore, Probability that Sum of numbers is 10 = 3/36 => 1/12

The correct answer is **Option A**