Zensar Recruitment Aptitude Questions

   

Zensar Recruitment - Quantitative Aptitude Questions

Is Zensar technologies visiting your campus? Are you looking for good resources to get yourself ready for the placement challenge? Here are a set of Quant questions based on previous years’ Zensar Placement Papers.

Zensar Online Test pattern consists of two major sections which are Aptitude Section and Technical Section with a total of 50 questions in 50 minutes. Aptitude Section consists of 30 questions related to quant, reasoning and verbal and the time allotted for this sections is 30 minutes. 

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Zensar Quantitative Aptitude Questions and Answers

This article covers some of the quant question based on the previous year’s pattern related to Speed and Time, Algebra, Equations, Progression, profit and Loss, Ratios, Averages and Geometry.

You can go through the following sample questions to make yourself ready for Zensar Placement Test.

Directions for Questions 1 to 8: Choose the correct options in the below questions.

1. The average score of Indian cricket team in the last 15 matches is 242 runs. If the average score in the first five matches is 280, then what is the average score of Indian cricket team in last 10 matches?

a) 223

b) 280

c) 240

d) 232

Explanation:

Average Score = 242, Number of Matches = 15 => Total Runs scored in all 15 matches = 242 * 15 = 3630

Average score of first 5 matches = 280 => Total runs scored in first 5 matches = 280 * 5 = 1400

So, runs scored in last 10 matches = 3630 – 1400 = 2230

Hence, average of runs in last 10 matches = 2230/10 = 223

Therefore, the correct answer is Option A

2. The simple interest accumulated on an amount in 4 years with an interest rate of 8% is 3200. What will be the compound interest accumulated on the same amount of money for 3 years at 5 percent interest rate?

a) 1675.25

b) 1576.25

c) 1500

d) 1476.25

Explanation:

Simple Interest = (P*R*T)/100 => 3200 = P*8*4/100  P = 10000

Now, Compound Interest = A – P = P(1+(R/100)^t –P => P[(1+(R/100)^t – 1]

=> 10000 [(1 + 0.05)^3 -1]

=> 10000 (1.157625 – 1)

=> 1576.25

Therefore, the correct answer is Option B

3.  5 * 135 / 9 + 242 / 11 * 16 – 34 =?

a) 427.09

b) 86.87

c) 393.00

d) 42.375

Explanation:

We need to follow BODMAS rule in this question. According to this question, first we will do division, then multiplication then addition and in last subtraction

So, 5 * 15 + 22 * 16 – 34 => 75 + 352 – 34 => 427 -34 = 393

Therefore, the correct answer is Option C

4. What will come in the place of question mark in the below-given sequence?

1, 5, 14, 30, ? , 91, 140

a) 60

b) 25

c) 49

d) 55

Explanation:

The sequence here is 1^2, (1^2 + 2^2), (1^2 + 2^2 + 3^2) and so on

So, the number will be (1^2 + 2^2 + 3^2 + 4^2 + 5^2) = 55

Therefore, the correct answer is Option D

5. There are two numbers X and Y. Square of Y multiply by 6 is equal to 540 more than the square of A, and the ratio between X and Y is 3:2. Find out the value of Y?

a) 12

b) 16

c) 8

d) 10

Explanation:

As per the given statement in question

6 * Y^2 = X^2 + 540 and X : Y = 3 : 2

By solving both the equations in term of Y, we will get

6 * Y^2 = (1.5Y)^2 + 540

=> Y = 12

Therefore, the correct answer is option A.

6.  A certain number of pens can be purchased for Rupees 216, 15 more pens could have been purchased with the same amount of rupees 216, if the cost of each pen is reduced by rupees 10. What was the number of pens purchased?

a) 9

b) 14

c) 12

d) 10

Explanation:

Let ‘X’ be the number of pens purchased and ‘Y’ be the cost of each pen

Therefore, Y = 216/X and Y-10 = 216/(X+15)

By solving both the equations in terms of X we get

216/X – 216/(X+15) = 10

=> X = 12

Therefore, the correct answer is Option C

7. (1218.64 + 2129.36 – 1573.94) / 4.5 = ?

a) 326.235

b) 394.235

c) 425.235

d) 272.235

Explanation:

(1218.64 + 2129.36 – 1573.94) / 4.5 → 1774.06 / 4.5 => 394.235

Therefore, the correct answer is Option B

8. A train of length 200 m is travelling with a speed of 120 Kmph and other train coming from the opposite direction is travelling with a speed of 80 Kmph. Both the trains cross each other in 9 seconds. Find the length of the other train (mark the approximate answer if not an integer).

a) 275

b) 260

c) 240

d) 300

Explanation:

Speed of trains in m/sec

I. 120 kmph = (120 * 1000) / 3600 = 33.33 m/sec

II. 80 kmph = (80 * 1000) / 3600 = 22.22 m/sec

Now, Time taken to cross each other = total length / relative speed => 9 = (200 + L) / 55.55

=> L ~300 m

Therefore, the correct answer is Option D

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